If z=x+iy where x,y are real ,prove that |x|+|y|less than equal to 2|z|.

We know , Square of any real number is always greater than or equal to zero.So,x-y20x2+y2-2 x y0x2+y22 x yAdding x2+y2 on both sides 2x2+y2 x2+y2+2 x y2z2x+y2Both the term are positive , so we can take the square root without disturbing inequality.2 zx + yx + y2 zHence Proved.

  • 24
What are you looking for?