If z=x+iy where x,y are real ,prove that |x|+|y|less than equal to 2|z|. Share with your friends Share 11 Rishabh Mittal answered this We know , Square of any real number is always greater than or equal to zero.So,x-y2≥0x2+y2-2 x y≥0x2+y2≥2 x yAdding x2+y2 on both sides 2x2+y2 ≥x2+y2+2 x y2z2≥x+y2Both the term are positive , so we can take the square root without disturbing inequality.2 z≥x + y⇒x + y≤2 zHence Proved. 24 View Full Answer