if zn2+/zn electrode is diluted 1000 times then the change in electrode potential is

Dear studentE =Eo-0.0592log[Zn2+]E=Eo-0.0592log[Zn2+]1000E-E0 =0.0059

Regards

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E=E• - 0.059/2 log [zn2+] Then, .Change in e, Eʿ=E• - 0.059/2 log [zn2+/1000]
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