If the normal to the parabola y2 = 4ax at the point (at2,2at ) cuts the parabola again at (aT2,2aT)then - Maths -

Question

I f   t h e   n o r m a l   t o   t h e  
p a r a b o l a   y 2   =   4 a x   a t  
t h e   p o i n t   ( a t 2 , 2 a t   )   c u t
s   t h e   p a r a b o l a   a g a i n   a t
  ( a T 2 , 2 a T ) t h e n   ( a )   - 2 ≤ T
≤ 2                
          ( b )   T ∈   (
- ∞ , - 8 ) ∪ ( 8 , ∞ ) ( c )   T 2 < 8
                 
                 
          ( d )   T 2 ≥ 8

Sakshi · Answer

This is the answer
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I f t h e n o r m a l t o t h e p a r a b o l a y 2 = 4 a x a t t h e p o i n t ( a t 2 , 2 a t ) c u t s t h e p a r a b o l a a g a i n a t ( a T 2 , 2 a T ) t h e n ( a ) - 2 ≤ T ≤ 2 ( b ) T ∈ ( - ∞ , - 8 ) ∪ ( 8 , ∞ ) ( c ) T 2 < 8 ( d ) T 2 ≥ 8

$I f t h e n o r m a l t o t h e p a r a b o l a y^{2} = 4 a x a t t h e p o i n t (a t^{2}, 2 a t) c u t s t h e p a r a b o l a a g a i n a t (a T^{2}, 2 a T) t h e n (a) - 2 \leq T \leq 2 (b) T \in (- \infty, - 8) \cup (8, \infty) (c) T^{2} < 8 (d) T^{2} \geq 8$