If x2+y2=25 , find d2ydx2 at x=0 - Maths - Application of Derivatives

Question

I f   x 2 + y 2 = 25   ,   f i n d   d 2 y d x
2   a t   x = 0

Aarushi Mishra · Accepted Answer

x2+y2=25Put x=0y2=25y=±5Differentiate both sides w
r t
  x2x+2ydydx=0  _______(1)dydx=-xyAt x=0dydx=0Differentiate equation 1 both sides w
r t
  x2+2yd2ydx2+2dydx2=0Therefore at x=0 y=±5 and dydx=02+2±5d2ydx2+0=01+±5d2ydx2=0d2ydx2=-1±5=±15

I f x 2 + y 2 = 25 , f i n d d 2 y d x 2 a t x = 0

$I f x^{2} + y^{2} = 25, f i n d \frac{d^{2} y}{d x^{2}} a t x = 0$