illustration -1:


Illustration 1 

CH3COOH + H2O CH3COO- + H30+; K1 = 1.8 x 10-5 
2H2 H3O + + OH- ; K2= 1 x 10-14
Calculate equilibrium constant for 

CH3COOH + OH-  CH3COO- + H2

The solution is as follows:

CH3COOH+H2O  CH3COO- +H3O+     K1 = 1.8×10-5  ..(12 H2O  OH- +H3O+                   K2 = 1×10-14     ..(2)Reversing reaction (2) and adding it to (1) CH3COOH+OH-  CH3COO- +H2O   K3 =K1×1K2 =1.8×10-510-14 = 1.8×1019

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