In a ΔABC, ∠B = 90°, AE = CD = 13 cm and BE = AD = 5 cm. Find BC


 

Dear student

In right angled triangle ABE,AB=AE2-BE2=132-52=12cmNow, BD=AB-AD=12-5=7cmTherefore, BC=CD2-BD2=132-72=169-49=120=230cm
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Tough!
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hm

 
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so 
 
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In triangle ABE,
Since AE = 13cm and BE = 5cm , AB = 12cm (pytha. triplet)

In triangle CBD,
BD =AB - AD
     = 12 - 5 = 7cm 

using pytha. theorem,
BC2 = CD2 - BD2
        = 132 - 72 
        = 169 - 49
       = 120
BC = root 120 .
 
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BC= 2√30
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