IN A CERTAIN FIRST ORDER REACTION , HALF THE RTEACTION WAS DECOMPOSED IN 500 SECONDS HOW LONG IT WILL BE UNTIL 1/10IS LEFT

ANS. 1661

Question

IN A CERTAIN FIRST ORDER REACTION , HALF THE RTEACTION WAS
DECOMPOSED IN 500 SECONDS HOW LONG IT WILL BE UNTIL 1/10IS LEFT
ANS 1661

Anita Dahiya · Accepted Answer

Half life = 500 seconds
t1/2 = 0 693 / k
k = 0 693/500
= 1 386 * 10^-3
When 1/10 of the reactant is left:
log (Xo/X) = kt / 2 30
Xo/X = 10 when 1/10 th of the reactant is left
log (10) * 2 3 / 1 386 * 10^-3
2 3 / 1 386 * 10^-3
= 1661 seconds

IN A CERTAIN FIRST ORDER REACTION , HALF THE RTEACTION WAS DECOMPOSED IN 500 SECONDS HOW LONG IT WILL BE UNTIL 1/10IS LEFT ANS. 1661

IN A CERTAIN FIRST ORDER REACTION , HALF THE RTEACTION WAS DECOMPOSED IN 500 SECONDS HOW LONG IT WILL BE UNTIL 1/10IS LEFT

ANS. 1661