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In a circle of radius 10.5 cm ,the minor arc is one-fifth the major arc.Find the area of the sector corresponding to the major arc.

radius of the circle r = 10.5 cm
and minor arc is one fifth of the major arc.
let the major arc subtend the angle θ on the circumference.
therefore minor arc subtend angle (360 - θ) on the circumference.
minor arc = 1/5* major arc
2πr*360-θ360=15*2πr*θ3605(360-θ)=θ1800-5θ=θ6θ=1800θ=18006=300
therefore the area of the sector corresponding to the major arc
=πr2*θ360=227*10.5*10.5*300360=33*10.5*56=288.75 cm2
hope this helps you.

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minor arc=1/5 of major arc

by applying ar of the arc for the minor arc

teta/360*2*22/7*10.5

since the minor arc is 5 times th majorthe angle is

360/5=72

substituting this in formulae

we get

13.2cm

now find circumfrence of the circle 2*pie*r

2*22/7*10.5=66cm

now since minor arc is 13.2 and cis 66

therefor major arc is 66-13.2=52.8

i think it helped u

in case of help pls ask

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