In a cricket match Gaurav faces 30 balls He hits 8 fours, 5 sixes and remaining singles in his - Maths - Probability

Question

In a cricket match Gaurav faces 30 balls He hits 8 fours, 5 sixes
and remaining singles in his score of 70 runs Find the probability
that on playing next ball Gaurav will 1) hit a sixer 2) make a
single run 3) not be able to score

Sd · Answer

No of runs = 70
No of runs made in fours = 8 x 4 = 32 => 8 balls
No of runs made in sixes = 5 x 6 = 30 => 5 balls
No of runs in singles = 70 - (32 + 30) = 8 => 8 balls [since, 1
single takes 1 ball]

Thus, no of no-score balls = 30 - (8 + 5 + 8) = 9

The probability we find is the chance of hitting a particular shot
in a ball

1) P(sixer) = No of favourable outcomes / total outcomes = 5 / 30 =
1/6

2) P(single run) = ​No of favourable outcomes / total
outcomes = 8 / 30 = 4/15

3) P(no score) = No of favourable outcomes / total outcomes = 9 /
30 = 3/10

In a cricket match Gaurav faces 30 balls. He hits 8 fours, 5 sixes and remaining singles in his score of 70 runs . Find the probability that on playing next ball Gaurav will. 1) hit a sixer 2) make a single run 3) not be able to score