in a cricket match karan faces 50 balls he hits 10 fours 5 sixes and remaining singles in his - Maths - Probability

Question

in a cricket match karan faces 50 balls he hits 10 fours 5 sixes
and remaining singles in his score of 82 on each ball karan faces
find
1 P(hitting a four)
2 P(single run)
3 P(no run)

Manbar Singh · Accepted Answer

Total number of balls faced = 50Total number of possible outcomes = 50It is given that he hits 10 boundaries and 5 sixes
Number of balls in which he score boundaries = 10Number of balls in which he scores six = 5Total runs in boundaries and sixes = 10×4+5×6 = 40+30 = 70Total runs scored = 82So, runs scored in singles = 82 - 70 = 12Number of balls faced for singles = 121
Number of balls in which he score boundaries = 10Number of favourable outcomes = 10Phitting 4 = Number of favourable outcomesTotal number of possible outcomes  = 1050 = 152
Number of balls in which he scores sixes=5Number of favourable outcomes = 5Phitting 6 = Number of favourable outcomesTotal number of possible outcomes  = 550 = 1103
Number of balls in which he does not score run = 50 - 10+5+12 = 50 - 27 = 23Number of favourable outcomes = 23Pno run = Number of favourable outcomesTotal number of possible outcomes  = 2350

in a cricket match karan faces 50 balls .he hits 10 fours 5 sixes and remaining singles in his score of 82 .on each ball karan faces find. 1. P(hitting a four) 2. P(single run) 3. P(no run)

in a cricket match karan faces 50 balls .he hits 10 fours 5 sixes and remaining singles in his score of 82 .on each ball karan faces find.
1. P(hitting a four)
2. P(single run)
3. P(no run)