In a crystalline solids,anion C are arranged in ccp .cation A occupy 50%of the tetrahedral voids and cation B occupy 50% of the octahedral voids.what is the formula of the solid?
In a ccp arrangement, number of atom per unit cell = 4
So, number of anions, C = 4
Number of tetrahedral voids = 8
Number of A atoms in tetrahedral voids = (50/100) x 8 = 4
Number of octahedral voids = 4
Number of B atoms in octahedral voids= (50/100) x 4 = 2
Hence, the formula of the solid = A4B2C4
So, number of anions, C = 4
Number of tetrahedral voids = 8
Number of A atoms in tetrahedral voids = (50/100) x 8 = 4
Number of octahedral voids = 4
Number of B atoms in octahedral voids= (50/100) x 4 = 2
Hence, the formula of the solid = A4B2C4