In a house, 3 bulbs of 100 watt each are lighted for 5 hours daily, 2 fans of 50 watt - Physics - Electricity

Question

In a house, 3 bulbs of 100 watt each are lighted for 5 hours daily,
2 fans of 50 watt each are used for 10 hours daily and an electric
heater of 1 kW is used for half an hour daily Calculate the total
energy consumed in a month of 31 days and it’s cost at the
rate of ₹3 60/kWh
PLEASE ANSWER FAST!!!!!!

Debalina Deb · Accepted Answer

Dear student,
3 bulbs of each 100 watt power; hence power consumption in 3 bulbs = 3×100=300 watttime =5hrenergy consumption by 3 bulbs = 5×300=1500 Watt-hr2 fans of 50 watt each; hence power consumption in 2 fans= 2×50=100 watttime =10 hrenergy consumption in 2 fans =10×100=1000 watt-hrpower consumption in electric kettle =1 KW =1000 watttime = 30 min =0
5 hrenergy consumption in electric kettle = 0
5×1000=500 watt-hrtotal energy consumption = 1500+1000+500=3000 watt-hr =3 kWh Now in 31 days, total eenrgy consumption =31×3 kWh =93 kWhnow 1 kWh costs 3
6 INRthen for 3 kWh cost will be =334
8 INR

Regards,