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In a house 3 bulbs of 100 watt each lighted for 5 hours daily, 2 fans of 50 watt each used for 10 hours daily and an electric heater of 1.00 kW is used for half an hour daily.
Calculate the total energy consumed in a month of 31 days and its cost at the rate of Rs 3.60 per kWh.
This question came for the SA-1 science exam which we had today.
HOPE you can answer it ;]
I need the answer quickely........

Kindly refer to the link given below for an answer to a  similar query :
https://www.meritnation.com/ask-answer/question/in-mrs-pintos-flat-there-are-6-bulbs-of-100-w-each/electric-energy-power-and-household-circuits/8869433

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3bulb of 100 w for 5 hrs.
3 ×100×5 = 1500 w = 3/2 kwh
2 × 50 × 10 = 1000 w = 1 kwh.
1 kwh × 1/2 hr = 1/2 kwh.
for 31 days.
3/2 × 31 = 93/2
1 × 31 = 31
1/2 × 31 = 31 / 2.
now adding these
93/2 + 31/2 + 62/2 = 196/2.
= 98.
now cost is 98 × 3.6
= rs. 352.8
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