In a linear chromosome, map distances between four loci are as follows: a-b-10, b-c-4, a-d-3, a-c-6. the expected cross over frequency between c and d is-

a) 3%

b)9%

c) either 3%or 9%

d)4% to 12%

plz provide the solution

1 ​map unit (m.u.) = 1% frequency.

Here a-c = 6 m.u i.e 6%
and a-d = 3 m.u i.e 3%

There frequency for c-d = a-c + a-d = 6% + 3% x 100

6100+3100 ×100 =9%

The correct answer is b.
 

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