In a linear chromosome, map distances between four loci are as follows: a-b-10, b-c-4, a-d-3, a-c-6. the expected cross over frequency between c and d is-
a) 3%
b)9%
c) either 3%or 9%
d)4% to 12%
plz provide the solution
1 map unit (m.u.) = 1% frequency.
Here a-c = 6 m.u i.e 6%
and a-d = 3 m.u i.e 3%
There frequency for c-d = a-c + a-d = 6% + 3% x 100
The correct answer is b.
Here a-c = 6 m.u i.e 6%
and a-d = 3 m.u i.e 3%
There frequency for c-d = a-c + a-d = 6% + 3% x 100
The correct answer is b.