# In a mixture of 60 litres, the ratio of milk and water is 2 : 1. If if this ratio is to ne 1 : 2 then the quantity of water to be further added is

$Quantityofmilk=\left(60\times \frac{2}{3}\right)litres=40litres\phantom{\rule{0ex}{0ex}}Quantityofwaterinit=\left(60-40\right)litres=20litres\phantom{\rule{0ex}{0ex}}Newratio=1:2\phantom{\rule{0ex}{0ex}}Letquantityofwatertobeaddedfurtherbexlitres\phantom{\rule{0ex}{0ex}}Then,Milk:Water=\left(\frac{40}{20+x}\right)\phantom{\rule{0ex}{0ex}}Now,\left(\frac{40}{20+x}\right)=\frac{1}{2}\phantom{\rule{0ex}{0ex}}20+x=80\phantom{\rule{0ex}{0ex}}x=60\phantom{\rule{0ex}{0ex}}Quantityofwatertoaddedis60litres.$

Regards

**
**