In a one day cricket match,Sachin played 40 balls and hit 12 sixes and saurav played 30 balls and hit 9 fours.Find the probability that Sachin will hit a six in the next ball and also find the probability that saurav will not hit a four in the next ball.

Given Sachin hit 12 sixes in 40 ballsHence probability of hitting six in next ball =favourable number of outcomestotal number of outcomesNow favourable number of outcomes =12 Total number of outcomes = total number of ballsProbability that next ball goes for a six = 1240=310Saurav hit 9 fours in 30 balls.Probability of hitting a four in next ball = favourable number of outcomestotal number of outcomesNow favourable number of outcomes =9 Total number of outcomes = total number of balls=30Probability that next ball goes for a four = 930=310Hence Probability that next ball not going for a four =1-Probability that next ball goes for a four=1-310=710

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