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In a parallelogram ABCD,AB=8 cm.The altitudes corresponding to side AB and AD are respecyvely 4cm and 5cm.Find measure of AD.

Please answer quckly i have exam tommorow.

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https://www.meritnation.com/ask-answer/question/cm-the-altitudes-corresponding-to-the-sides-ab-and-ad-a/understanding-quadrilaterals/6345316

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In parallelogram ABCD, AB is the base and let DF be the corresponding altitude.Therefore, Area of the parallelogram ABCD = bh = DF X AB = 4 X 8 = 32 sq. cmSince Area = bh, that is also equal to base DA multiplied by the corresponding altitude BE.That implies, Area of the parallelogram = AD X BE = 5BE = 32

That implies BE = 32 / 5 = 6.4 cm

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Thanks buddy! :)

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