In a parallelogram ABCD, angle A = 2x+25, angle B= 3x-5. Find the value of x, and he value of each angle in the parallelogram.

Dear Student,

 As A and B are adjacent angles in the parallelogram,therefore,A + B = 180°2x+25 + 3x-5 = 1805x + 20 = 1805x = 180 - 205x = 160x = 1605 = 32A = C = 2x+25° = 89°  As opposite angles in parallelogram are equalB = D = 3x-5° = 91°  As opposite angles in parallelogram are equal
Regards,

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In parallelogram opposite angles are supplementary. Therefore ∠B +∠D=180° 2x+25+3x−5=180° x= 180−20/5 =32 ∠B=2x+25=(2∗32)+25= 89° ∠D=3x−5=(3∗32)−5= 91°
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