In a quadrilateral PQRS, the bisector of <R and < S meet at point T . Show that <P + < Q = 2 < RTS.

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  • ½ R + ½ S + T = 180
  • ½ (R+S) + T= 180
  • ½ (360 – (P+Q)) + T = 180
  • 180 – 1/2 (P+Q) + T = 180
  • T  – 1/2 (P+Q) = 180 – 180
  • T  – 1/2 (P+Q) = 0
  • T = 1/2 (P+Q)
  • T *2 = P+Q
  • 2T = P+Q
  • PROVED!!!!!!
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