In a radio active material the activity at time t1 is R1 and at a later time t2 is R2 - Physics - Nuclei

Question

In a radio active material the activity at time t1 is R1 and at
a later time t2 is R2 If the decay constant of the material is
(lambda) then,
1-R1=R2
2-R1=R2e^(-lambda)(t1-t2)
3-R1=R2e^(lambda)(t1-t2)
4-R1=R2(t2/t1)

Kumar Prabhat · Accepted Answer

dN/dt1 (=R1) = -lambdaN
dN/dt2 (=R2) = -lambdaN'
But,
N'/N = e raise to the power
(-lambda(t2-t1))
Therefore, R2 / R1 = e raise to the power
(-lambda(t2-t1))
Or, R1 = R2 e raise to the power
(lambda(t2-t1)) = R2 e raise to
the power (-lambda(t1-t2))

In a radio active material the activity at time t1 is R1 and at a later time t2 is R2. If the decay constant of the material is (lambda) then, 1-R1=R2 2-R1=R2e^(-lambda)(t1-t2) 3-R1=R2e^(lambda)(t1-t2) 4-R1=R2(t2/t1)

In a radio active material the activity at time t1 is R1 and at a later time t2 is R2. If the decay constant of the material is (lambda) then,

1-R1=R2

2-R1=R2e^(-lambda)(t1-t2)

3-R1=R2e^(lambda)(t1-t2)

4-R1=R2(t2/t1)