In a reaction, 2X+Y =X2Y, the  X disappears at?
A) twice the rate that of appearance of X2Y
​B) half the rate as that of disappearance of Y
please solve it!!!
 

Dear student,

In this chemical reaction:

2X + Y  ----> X2Y


Rate = -12ΔXΔt=-ΔYΔt=ΔX2YΔtorRate =- ΔXΔt=-2ΔYΔt=2ΔX2YΔt

Hence, we can conclude from the above expression that, rate of disappearance of X is equal to twice the rate of disappearance of Y or twice the rate of appearance of X2Y.

Therefore, from above options, option (A) is correct.

Best Wishes !

  • 12
From the given chemical equation,
1/2 -(d[X]/dt) = -d[Y]/dt = d[X2Y]/dt
d[X]/dt = 2 d[X2Y]/dt
Option A is correct.
d[X]/dt = 2 d[Y]/dt
​B is wrong.
 
  • 3
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