In a regular hexagon ABCDEF, prove that-

AB +AC + AD + AE + AF = 3AD = 6AO ; where O is the centre of the hexagon.

( AB, AC...AO- are all vectors)

Question

In a regular hexagon ABCDEF, prove that-
AB +AC + AD + AE + AF = 3AD = 6AO ; where O is the centre of the
hexagon
( AB, AC AO- are all vectors)

Andra · Answer

AB+AC+AD+AE+AF= ao + ob+ ao + oc + ao+ od + ao+ oe+ ao + of=
6aoBecause OB=-OEOC=-OFOD=AO (All vectors)