In a saturated solution of calcium phosphate , the conc. Of PO4^3- is 3.3×10^-7. The Ksp of Ca3(PO4)2 is

Dear Student,

The reaction can be described as:
$$\begin{gathered} C{a}_3(P{O}_4{)}_2 \to 3C{a}^{2+} + 2P{O_4}^{3-} \\ The molar ratio for C{a}^{2+ }and P{O_4}^{3-} is 3:2. \\ For 3 moles of C{a}^{2+ }, 2 moles of P{O_4}^{3-} are required. \\ Concentration of P{O_4}^{3-}=3.3 \times {10}^{-7} M \\ So, concentration of C{a}^{2+ }=\frac{3.3 \times {10}^{-7} \times 3}{2}=4.95 \times {10}^{-7} M \\ Now, \\ {K}_{sp}=(C{a}^{2+ }{)}^3 (P{O_4}^{3-}{)}^2=(4.95 \times {10}^{-7}{)}^3(3.3 \times {10}^{-7}{)}^2= 1.32 x {10}^{-32} \end{gathered}$$

Thus, the K_sp of Ca₃(PO₄)₂ is 1.32 x 10^-32.

Hope it helps.

Regards