in a series l R circuit ,L=35 mH and R=11 ohm , v=v sin omega t v rms =220  V and frequency 50 Hz are applied .find the current amplitude in the circuit and phase of current with respect to voltage.draw reactance-frequency graph

$$\begin{gathered} Dear student \\ \omega =2\pi f \\ =100\pi \\ {X}_L=\omega L=100\pi \times 0.035=3.5\pi \\ R=11 \\ Z=11+3.5\pi =22 ohms \\ \frac{V_0}{\sqrt{2}}=220 \\ {V}_0=311.{12}_{ \\ } \\ {I}_0=\frac{V_0}{Z}=\frac{311.12}{22} \\ =14.14 amp \\ phase \varphi = {\tan }^{-1}\left(\frac{X_L}{R}\right)={\tan }^{-1}\left(\frac{11}{11}\right)={45}^0 \\ approx \end{gathered}$$

note:
This graph just representative. It is not exact because frequency is fixed, so a continuous graph between X or Z and frequency cannot be plotted, we obtain points only. these points are shown in above graph s he meeting points of X and Y axis: This is a representation that f=50 Hz, we get X_L=11 and Z=22. A phasor diagram showing R, X_L and Z or V and I could be better shown