in a single throw of two dice,find the probability of getting
a total of 7
a total of 11
six as product

not sure but may be :
1/9 
1/18  
1/9
  • -1
Sample Space =
{(1,1) (1,2) (1,3) (1,4) (1,5) (1,6)
  (2,1) (2,2) (2,3) (2,4) (2,5) (2,6)
  (3,1) (3,2) (3,3) (3,4) (3,5) (3,6)
  (4,1) (4,2) (4,3) (4,4) (4,5) (4,6)
  (5,1) (5,2) (5,3) (5,4) (5,5) (5,6)
  (6,1) (6,2) (6,3) (6,4) (6,5) (6,6)}

A) A total of  7 =
(1,6) (2,5) (3,4) (4,3) (5,2) (6,1) = 6 chances
Probability( getting total of 7) = 6/36 =1/6
 
B) A total of 11=
(5,6) (6,5) = 2 chances
Probability(of getting total 11) = 2/36 = 1/18 

C) 6 as product =
(1,6) (2,3) (3,2) (6,1)  = 4 chances
Probability(of getting 6 as a product) = 4/36 = 1/9


 
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