In a solid AB having the NaCl structure, A atoms occupy the corners of the cubic unit cell If - Chemistry -

Question

In a solid AB having the NaCl structure, A atoms occupy the corners
of the cubic unit cell If all the face-centered atoms along one of
the axes are removed, then the resultant stoichiometry of the solid
is

(A) AB2 (B) A2B (C)
A4B3 (D) A3B4

Vartika Jain · Accepted Answer

Dear Student,

AB has NaCl structure
 So, obe type of atom must be arranged in FCC pattern and other type of atoms must be present on all the 12 edges as well as at the center pg the unit cell Since A atoms are occupying the corners of unit cell, they must also be arranged on the face cebtres
The B atoms can be found at the 12 edges and at the center of the unit cell
 Therefore, before removing face centred atoms :No
 of A atoms =8×18+6×12=1+3=4No
 of B atoms =12×14+1×1=3+1=4After removing face centred A atoms along one of the axesNo
 of A atoms = 8×18+4×12=1+2=3No
 of B atoms =12×14+1×1=3+1=4Therefore, stoichiometry after removing these atoms in A3B4

In a solid AB having the NaCl structure, A atoms occupy the corners of the cubic unit cell. If all the face-centered atoms along one of the axes are removed, then the resultant stoichiometry of the solid is (A) AB2 (B) A2B (C) A4B3 (D) A3B4

In a solid AB having the NaCl structure, A atoms occupy the corners of the cubic unit cell. If all the face-centered atoms along one of the axes are removed, then the resultant stoichiometry of the solid is

(A) AB₂ (B) A₂B (C) A₄B₃ (D) A₃B₄