In a trapezium ABCD, AB || DC, Angle A : Angle D = 3 : 5, Angle B = (6x + 10)
Angle C = (3x - 10). Find each angle of trapezium.

Question

In a trapezium ABCD, AB || DC, Angle A : Angle D = 3 : 5, Angle B =
(6x + 10)
Angle C = (3x - 10) Find each angle of trapezium

Gursheen Kaur · Accepted Answer

<img alt="" src=
"https://s3mn%20mnimgs%20com/img/shared/content_ck_images/ck_601ff3615c2ca%20jpg"
style="width: 50px; height: 17px;">
Therefore,
angle A=3×210 = 630
angle B=6(210)+10 = 1360
angle C=3(210)-10 = 530
angle D=5(210) = 1050
Regards!

In a trapezium ABCD, AB || DC, Angle A : Angle D = 3 : 5, Angle B = (6x + 10) Angle C = (3x - 10). Find each angle of trapezium.

In a trapezium ABCD, AB || DC, Angle A : Angle D = 3 : 5, Angle B = (6x + 10)
Angle C = (3x - 10). Find each angle of trapezium.