in a triangle abc ab =ac,ba is produced to d and ae is drawn parallel to bc ,prove that ae bisects angle dac Share with your friends Share 0 Neha Sethi answered this Given △ABC, AB=ACAE∥BC⇒∠3=∠2 ...1 alternate interior anglesNow, ∠3+∠4=∠1+∠2 exterior angle property⇒∠2+∠4=∠1+∠2 using 1⇒∠4=∠1 ...2But ∠1=∠2 angles opposite to equal sides AB=AC are equal.⇒∠1=∠2=∠3 using 1⇒∠1=∠3 ...3From 2 and 3, we get∠3=∠4⇒AE bisects ∠DAC -1 View Full Answer