In a triangle ABC angle A =90? CA= AB Prove that : DC^2 - BD^2 =2?AB?AD Share with your friends Share 0 Sneha Apar answered this Dear student, Assuming your question to be, In∆ACDapplying Pythagoras theoremCD2=AC2+AD2CD2=AC2+AB+BD2CD2=AC2+AB2+BD2+2AB.BDCD2-BD2=BC2+2AB AD-ABCD2-BD2=BC2-2AB2+2AB.AD ....1from ∆ABC,BC2 = AC2+AB2 Pythagoras theoremBC2 = AB2 + AB2 as, AB = ACBC=2ABNow, from 1, CD2-BD2=2AB2-2AB2+2AB.ADCD2-BD2=2AB.AD Regards 0 View Full Answer