In a triangle ABC angle A =90?
CA= AB
Prove that : DC^2 - BD^2 =2?AB?AD

Dear student,

Assuming your question to be,


InACDapplying Pythagoras theoremCD2=AC2+AD2CD2=AC2+AB+BD2CD2=AC2+AB2+BD2+2AB.BDCD2-BD2=BC2+2AB AD-ABCD2-BD2=BC2-2AB2+2AB.AD       ....1from ABC,BC2 = AC2+AB2   Pythagoras theoremBC2 = AB2 + AB2    as, AB = ACBC=2ABNow, from 1, CD2-BD2=2AB2-2AB2+2AB.ADCD2-BD2=2AB.AD

Regards

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