In a triangle ABC,DE is parallel to BC and D is the midpoint of side AB.Find the perimeter of triangle ABC when AE=4.5cm,DE=5cm and DB=3.5 cm
Please find below the solution to the asked query:
From given information we form our diagram , As :
Here , BC | | DE and D is mid point of AB , So
DB = AD = 3.5 cm ( As given DB = 3.5 cm )
From converse of mid point theorem we get
And if D is mid point of AB and DE | | BC , so from converse of mid point theorem we get that E is mid point of AC , So
AE = CE = 4.5 cm ( As given AE = 4.5 cm )
AC = AE + CE = 4.5 + 4.5 = 9 cm
Perimeter of triangle ABC = AB + BC + AC = 10 + 7 + 9 = 26 cm ( Ans )
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