In a triangle ABC, if 3 A = 4 B = 6C ,then angle A, angle B, angle C respectively ,are

Let 3A = 4B = 6C = k

 

so, A = 240 / 3 = 80°

B = 240 / 4 = 600

C = 240 / 6 = 400

  • 53

A=x/3 B=x/4 c=x/6

A+B+C=180

x/3+x/4+x/6=180

9x/12=180

x=240

a=80 B=60 C=40

  • 15
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