In a triangle ABC,if angle A+B=110 and angle B+C=132,then find angle A,B and C - Maths - Lines and Angles

Question

In a triangle ABC,if angle A+B=110 and angle B+C=132,then find
angle A,B and C

Abhishek Jha · Accepted Answer

Dear Student,
Here is the solution of your asked query:
∠A+∠B=110    
(i)∠B+∠C=132   
(ii)We know that sum of angles of triangle is 180 so we have;∠A+∠B+∠C=180⇒110+∠C=180            {using (i)}⇒∠C=70∠B=132-70=62Then, ∠A=110-62=48
Regards

In a triangle ABC,if angle A+B=110 and angle B+C=132,then find angle A,B and C.