in a triangle abc, right -angled at b,ab=45  bc=14. Find sin b,cos b.                                  

 

 

IS THIS POSSIBLE!!!!!!!!!!!!!!!!!!!!! ( WHY )

 This Triangle is not possible

As Sine and Cosine are for acute angle.Therfore sin B and cos B cannot be determined for the above triangle.

However,sin 90^o=1 and cos 90^o=0

 this triangle is not possible but 

sinB=p / h

cosB=b/h

thanks