In a two digit number, the digit at unit's place is equal to the square of the digit at ten's place, if 54 is added to the number the digit gets interchanged. Find the number.

Let the digit at tens place = xSo, the digit at units place = x2Now, original number = 10×x + x2 = 10x + x2Now, when the digits are interchanged, then new number = 10x2+xNow, according to question :10x + x2 + 54 = 10x2 + x10x2 + x = 10x + x2 + 549x2 - 9x - 54 = 0x2 - x - 6 = 0x2 - 3x + 2x - 6 = 0xx - 3 + 2x - 3 = 0x - 3x + 2 = 0x - 3 = 0  or   x + 2 = 0x = 3  or  x = -2 rejectedSo, original number = 10×3 + 32 = 30 + 9 = 39

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