in a unit cell, atoms A,B,C,D are present at half of total corners, all face-centres, body centre and one third - Chemistry - The Solid State

Question

in a unit cell, atoms A,B,C,D are present at half of total corners,
all face-centres, body centre and one third of all edge-centres
respectively then formula of unit cell is??
1)AB3CD3 2)ABCD
3)AB6C2D2
4)AB6C2D4

veena Vasandani · Accepted Answer

Atoms at the corner in a unit cell is
1
No of atoms of A in one unit cell =
½

Atoms at the corner in a unit cell is
3
No of atoms of B in one unit cell =
3

Atoms at the body center in a unit cell is
1
No of atoms of C in one unit cell =
1

Atoms at the edge center in a unit cell is
3
No of atoms of D in one unit cell =
1

Formula is A1/2B3CD or
AB6C2D2

in a unit cell, atoms A,B,C,D are present at half of total corners, all face-centres, body centre and one third of all edge-centres respectively. then formula of unit cell is??1)AB3CD3 2)ABCD 3)AB6C2D2 4)AB6C2D4

in a unit cell, atoms A,B,C,D are present at half of total corners, all face-centres, body centre and one third of all edge-centres respectively. then formula of unit cell is??
1)AB₃CD₃ 2)ABCD 3)AB₆C₂D₂ 4)AB₆C₂D₄