In a Young's double slit experiment distance between the slits is 1 mm The fringe width is found to be - Physics - Wave Optics

Question

In a Young's double slit experiment distance between the slits is 1
mm The fringe width is found to be 0 6 mm When the screen is moved
through a distance of 0 25 m away from the plane of the slit, the
fringe width beces 0 75 mm Find the wavelength of light used

Neha Gupta · Accepted Answer

fringe width is given by:β = λDdd = distance between the slitsD is the distance between the screens and slit
d = 1 mm = 0 001 m0
6×10-3 = λD0 0010
75×10-3 =  λD+0 250 0010 750
6 = D+0 25D = 1 25D +0 25 = 1
25 D0 25 = 0 25 DD = 1mtherefore0
6×10-3 = λ×10 001λ = 0
6×10-6 m

In a Young's double slit experiment distance between the slits is 1 mm.The fringe width is found to be 0.6 mm.When the screen is moved through a distance of 0.25 m away from the plane of the slit, the fringe width beces 0.75 mm.Find the wavelength of light used.