In ∆ABC , DE ║ BC. If BD = x – 3, AB = 2x, CE = x -2 and AC = 2x + 3.Find x. Share with your friends Share 0 Shivshankar Kumar answered this Dear student, Regards. 2 View Full Answer Aditya Pratap Singh answered this Since DE is parallel to BC by basic proportionality theorem (AB/DB)=(AC/EC) (2x/x-3)=(2x+3/x-2) By cross multiplication we get , 2 x2- 4x = 2 x2 - 3x -9 -4x=-3x-9 -x=-9 x=9 4
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