In an a.c circuit, instantaneous voltage and current are V=200sin300t volts and I=8cos300t Amp respectively. What is the average power dissipated in the circuit ? Why ?

Given
V=200 sin(300t)I=8cos(300t)=8sin(300t+π2)So, Instantaneous Voltage, V0=200VInstantaneous Current, I0=8APhase between I and V, ϕ=π2We know thatAverage Power Dissipated in the circuit is given asPavg=12I0V0cosϕ=12×8×200×cos(π2)=0W 
Therefore, Average Power Dissipated in the given A.C. circuit will be 0 Watt.

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