in an adsorption experiment a graph between logx/m vs logp is found to be linear with a slope of 45degree. the intercept of thelogx/m axis was found to be 0.3010 what is the x/m axis if the pressure is 0.6bar?

Dear student
Please find the solution to the asked query:

Freundlich adsortion isotherm tells us about the quantity of gas adsorbed by unit mass of solid adsorbent with pressure.It is given by the formula:-
here :-

x= mass of adsorbate

m= mass of adsorbent

p = equilibrium pressure of adsorbate

K and n are constants
Intercept of the axis = logK = 0.3010
​Slope =1/n = 45^o
​Pressure, p =0.6 bar

Substituting the values we get:



$\frac{x}{m}=k{p}^{1/n}$
$$\begin{gathered} \log \frac{x}{m}=\log K +\frac{1}{n}\log p \\ \log \frac{x}{m}=0.3010+ 45[\log 0.6] \\ \log \frac{x}{m}=0.3010 +(-9.983) \\ \log \frac{x}{m}=-9.682 \end{gathered}$$
x/m = antilog (-9.682)
x/m = 2.07 x 10^-10


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