In an apparatus, the electric field was found to oscillate with an amplitude of 18Vm-1. The magnitude of the oscillating magnetic field will be Share with your friends Share 6 Aman Prakash answered this Please find this answer -1 View Full Answer Muskaan Gandhi answered this What is B and E? 2 Aman Prakash answered this B-Magnetic field E-Electric field 2 Supreeth answered this Use c=E/B ~B=E/C C=speed of light E=18v/m -1 Joy answered this amplitude =18 V/m B0=E0/c [here c is the velocity of light] {B0= 18/3*10^-8} 3 Joy answered this so finally you will get 6*10^-8 HOPE THIS WILL HELP YOU..... -1 Rishika Mathur answered this Bo=Eo÷c , put the values u will get ur ans -1
