in an electric circuit with a resistance wire and a cell, the current flowing is I. What would happen to this current if the wire is replaced by another thicker wire of same material and same length? give reason

The current will increase.

This will happens because a thicker wire of the same material will have a lower resistance. Now as the resistance is low current flowing in the wire gets lower resistance towards flow from the conductor and hence greater current flows. 

Let the original CSA of the wire be A1

So R1 = ρL/A1

  => ρL = R1 A1

Let the CSA of the thicker wire = A2

A2>A1

So R2 = ρL/A2

=> ρL = R2 A2

Thus,

R1A1 = R2A2

A2>A1

=> R1> R2

Now let the potential of the source be V

In First case

V = I1R1

In second case

V = I2R2

=> I1R1 = I2R2

Since R1>R2

=> I1 < I2

Thus current flow in the 2nd case will be greater.

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we know that

R=ΡL/A

V/I=PL/A (V/I=R)

SO........... I IS DIRCTLY PROPORTIONAL TO A(THICKNESS OF WIRE)

THIS IF WE REPLACE A THICKER WIRE THAN I ALSO INCREASE

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