In an experiment, refractive index of glass was observed to be 1 45, 1 56, 1 54, 1 44, 1 - Physics - Units And Measurements

Question

In an experiment, refractive index of glass was observed to be 1
45, 1 56, 1 54, 1 44, 1 54 and 1 53 Calculate (i) Mean value of
refractive index; (ii) Mean absolute error; (iii) Fractional error;
(iv) Percentage error Express the term as absolute error and
percentage error

Jyoti Pant · Accepted Answer

(i) Mean  value of refractive indexμ=1
45+1 56+1 54+1 44+1 54+1 536=1
51(ii) Absolute errors are:1 51-1 45=0 061 51-1
56=-0 051 51-1 54=-0 031 51-1 44=0 071 51-1 54=-0 031 51-1 53=-0
02Mean absolute error=±0 06+0 05+0 03+0 07+0 03+0
026=±0
04(iii) Fractional /Relative error=±0 041
51=±0 03(iv) Percentage error=±0
03×100=±3%So,μ=1 51±0 04or μ=1
51±3%

In an experiment, refractive index of glass was observed to be 1.45, 1.56, 1.54, 1.44, 1.54 and 1.53. Calculate (i) Mean value of refractive index; (ii) Mean absolute error; (iii) Fractional error; (iv) Percentage error. Express the term as absolute error and percentage error.