In an FCC arrangement of P and Q atoms, P atoms are at the corners of the unit cell, Q atoms at the face centres and two atoms are missing from two corners of each unit cell. What is the formula of the compound?
Number of atoms of P at the corners = 6 (because two P are missing)
Contribution atoms of P towards unit cell = 6 × 1/8 = 6
Number of atoms Q at face-centres = 6
Contribution of atom Q towards unit cell = 6 × 1/2 = 3
Ratio of P : Q = 6/8 : 3 or 3/4 : 3 = 3:12
Therefore the formula of the compound is A3B12