In an LCR circuit the resonating frequency is 500khz .If the value of L is doubled and the value of C is decreased to 1/8 times of its initial values then the new resonating frequency in khz is ... Share with your friends Share 4 Chakali Sudharshan answered this Dear student, Regards. 8 View Full Answer Ayush answered this Four times the original one. Since resonate frequency is given by f=(1/R)*(L/C)^1/2 1 Palash Patel answered this Hope you understand... 5 Akriti answered this thanks Palash -3 Palash Patel answered this My pleasure... -5