In BeO( Zinc Blende structure), Mg2+ is introduced in available tetrahedral voids. Then ions are removed from a single body diagonal of the unit cell. What will be the molecular formula of the unit cell?

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There are eight tetrahedral voids in BeO lattice (Zinc blende structure, fcc). If Mg²⁺ ions occupy all the tetrahedral voids then,
Number of Be²⁺ ions in tetrahedral voids = 4
Number of O²⁻ making the lattice = 4
Number of Mg²⁺ ions in tetrahedral voids = 4

If atoms along one body diagonal is removed then, 
Number of Be²⁺ ions in tetrahedral voids = 4
Number of O²⁻ making the lattice = 3/4
Number of Mg²⁺ ions in tetrahedral voids = 4

The formula of the compound is Be₄Mg₄O_3/4.

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