in [Cu(NH3)4]2+ WHY IS ONE ELECTRON SHIFTED FROM D ORBITAL TO P ORBITAL??
In [Cu(NH3)4]2+, the Cu exist in +2 oxidation state as, NH​3 is a neutral ligand witn charge = 0.
So, the Cu+ ion has d9 configuration, and here, NH3 acts as strong ligan which can form square planer complex by transferring 9th d electron to 4p-orbital and thus generates a dsp2 hybridization.
This transferrence of electron ocurs due to the strong field nature of the ammonia in contact of Cu-metal ion.
So, the Cu+ ion has d9 configuration, and here, NH3 acts as strong ligan which can form square planer complex by transferring 9th d electron to 4p-orbital and thus generates a dsp2 hybridization.
This transferrence of electron ocurs due to the strong field nature of the ammonia in contact of Cu-metal ion.