in d haber process,N2+3H2 gives 2NH3 ,,the rate of formation of ammonia is 4 8*10 to d power -3 mol/l/sec - Chemistry - Chemical Kinetics

Question

in d haber process,N2+3H2 gives 2NH3 ,,the rate of formation of
ammonia is 4 8*10 to d power -3 mol/l/sec ,,,,calculate the rate of
consumption of hydrogen ????

Neelam Yadav · Accepted Answer

Reaction is N2 + 3H2 ---->
2NH3
-d [N2] /dt = -1/3d [H2]/dt = 1/2
d[NH3]/dt
d [H2]/dt = 3 /2 x 4 8 x 10-3
= 7 2 x 10-3

in d haber process,N2+3H2 gives 2NH3.,,the rate of formation of ammonia is 4.8*10 to d power -3 mol/l/sec.,,,,calculate the rate of consumption of hydrogen.......????