In electrolytic refining, "The more basic metal remains in the solution and the less basic metal goes to the anode - Chemistry - General Principles and Processes of Isolation of Elements

Question

In electrolytic refining, "The more basic metal remains in the
solution and the less basic metal goes to the anode mud" pls
explain this statement

Prabhat Kumar · Accepted Answer

dear student
lets understand this statement via example of copper
In electrorefining of copper, there is transfer of pure metal from
anode to the cathode The voltage applied for electrolysis is such
that the impurities of more basic metals (more electropositive
metals) remain in solution as ions whereas impurities of the less
basic metals(less electropositive metals) settle down under the
anode as anode mud So the impurities of iron, nickel, zinc, and
cobalt present in blister copper being more electropositive pass
into solution as soluble sulphates while the impurities of
antimony, selenium, tellurium, gold, silver and platinum being
less electropositive are not affected by
CuSO4-H2SO4 solution and hence
settle under the anode as anode mud
regards

In electrolytic refining, "The more basic metal remains in the solution and the less basic metal goes to the anode mud"...pls explain this statement...