In example 10.1-gravitation.i am not getting the correct answer.could you please explain it to me.the complete steps are not given in the textbook.

The mass of the earth, M = 6 × 10²⁴ kg
The mass of the moon,
m = 7.4 × 10²² kg
The distance between the earth and the
moon,
d = 3.84 × 10⁵ km
  = 3.84 × 10⁵ × 1000 m
  = 3.84 × 10⁵⁺³ m = 3.84 ×10⁸ m
G = 6.7 × 10^–11 N m² kg^–2
= $$\begin{gathered} F =\frac{G\times M\times m}{d^2} \\ =\frac{{\mathrm{6.7\; \times \; 10}}^{–11}\times {\mathrm{6\; \times \; 10}}^{24 }\times {\mathrm{7.4\; \times \; 10}}^{22}}{({\mathrm{3.84\; \times \; 10}}^8{)}^2} \\ =\frac{6.7\times 6\times 7.4\times {10}^{-11+24+22}}{14.74\times {10}^{16}} \\ =\frac{297.48\times {10}^{-11+24+22-16}}{14.47} \\ = 20.1\times {10}^{19} = 2.01 \times {10}^{20 } \\ \mathrm{Thus,\; the} \mathrm{force} \mathrm{exerted} \mathrm{by} \mathrm{the} \mathrm{earth} \mathrm{on} t\mathrm{he} \mathrm{moon} \mathrm{is} {\mathrm{2.01\; \times \; 10}}^{20}N. \end{gathered}$$