In Fig. 2, ∠ABD = 66° and ∠ACB = 60°. If bisector of ∠A meets BC at D, find ∠ADB. Share with your friends Share 0 Shruti Tyagi answered this Dear student, We know,sum of angles of triangle is 180°⇒∠A+∠B+∠C=180°⇒66°+60°+a=180°⇒a=180°-126°⇒a=54°As AD is bisector of ∠BAC⇒∠BAD=54°2=27°Now in ∆ABD,⇒66°+27°+∠ADB=180°⇒∠ADB=180°-93°⇒∠ADB=87° Regards 1 View Full Answer