In Fig. 2, ∠ABD = 66° and ∠ACB = 60°. If bisector of ∠A meets BC at D, find ∠ADB.

Dear student,

We know,sum of angles of triangle is 180°A+B+C=180°66°+60°+a=180°a=180°-126°a=54°As AD is bisector of BACBAD=54°2=27°Now in ABD,66°+27°+ADB=180°ADB=180°-93°ADB=87°

Regards
 

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